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A charge ' $\mathrm{q}$ ' moves with a velocity $2 \mathrm{~ms}^{-1}$ along $\mathrm{x}$-axis in a uniform magnetic field $\vec{B}=(2 \hat{i}+2 \hat{j}+3 \hat{k}) T$, then charge will experience a force
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Verified Answer
The correct answer is:
In $y-z$ plane
Velocity of charge, $\overrightarrow{\mathrm{v}}=2 \mathrm{~m} / \mathrm{s}$ along $\mathrm{x}$ axis uniform magnetic field, $\vec{B}=(2 \hat{j}+2 \hat{j}+3 \hat{k}) T$
Change will experience a force
$$
\begin{aligned}
& F=q \vec{v} \times \vec{B}=q(2 \hat{j}) \times(2 \hat{i}+2 \hat{j}+3 \hat{k}) \\
& =q(4 \hat{k}-6 \hat{j})
\end{aligned}
$$
So, charge will experience a force in $\mathrm{y}-2$ plane.
Change will experience a force
$$
\begin{aligned}
& F=q \vec{v} \times \vec{B}=q(2 \hat{j}) \times(2 \hat{i}+2 \hat{j}+3 \hat{k}) \\
& =q(4 \hat{k}-6 \hat{j})
\end{aligned}
$$
So, charge will experience a force in $\mathrm{y}-2$ plane.
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