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A charged particle moves with constant velocity in a region where no effect of gravity is felt but an electrostatic field $\overrightarrow{\mathrm{E}}$
together with a magnetic field $\vec{B}$ may be present. Then which of the following cases are possible?
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together with a magnetic field $\vec{B}$ may be present. Then which of the following cases are possible?
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The correct answers are:
$\vec{E} \neq 0, \vec{B} \neq 0$, $\vec{E}=0, \vec{B}=0$, $\overrightarrow{\mathrm{E}}=0, \overrightarrow{\mathrm{B}} \neq 0$
If a charged particle is moving in a gravity-free space without changing its velocity, then three cases possible
(i) Particle can move with constant velocity in any direction, if \(\vec{E}=0, \vec{B}=0\).
(ii) If \(\vec{E}, \vec{B}\) are having values such that \(q E=q v B\) and hence both forces (Force due to magnetic field and force due to electric field) acts in such a way that they cancel each other, in this case also particle can move with uniform velocity.
(iii) If \(\vec{E}=0, \vec{B} \neq 0\) and \(\vec{B}\) is such that it acts in the direction of velocity then magnetic force would be zero and hence velocity can remain constant.
(i) Particle can move with constant velocity in any direction, if \(\vec{E}=0, \vec{B}=0\).
(ii) If \(\vec{E}, \vec{B}\) are having values such that \(q E=q v B\) and hence both forces (Force due to magnetic field and force due to electric field) acts in such a way that they cancel each other, in this case also particle can move with uniform velocity.
(iii) If \(\vec{E}=0, \vec{B} \neq 0\) and \(\vec{B}\) is such that it acts in the direction of velocity then magnetic force would be zero and hence velocity can remain constant.
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