A charged particle moving in a uniform magnetic field penetrates the layer of lead and thereby losses one-half of its kinetic energy. The radius of curvature of its path

Question

A charged particle moving in a uniform magnetic field penetrates the layer of lead and thereby losses one-half of its kinetic energy. The radius of curvature of its path, The radius reduces to r 2, The radius reduces to r 2, The radius remains the same, The radius becomes r 2

MARKS App · Accepted Answer

r = 2 m E q B and r ⁡ 1 = 2 m E ⁡ / 2 q B So, r ⁡ 1 = r ⁡ 2

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