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Question: Answered & Verified by Expert
A charged particle of mass m and charge q is projected into a uniform magnetic field of induction B with speed v which is perpendicular to B . The width of the magnetic field is d . The impulse imparted to the particle by the field is

d << mvqB

PhysicsMagnetic Effects of CurrentNEET
Options:
  • A qBv
  • B mvqB
  • C qBd
  • D 2 mv2qB
Solution:
1514 Upvotes Verified Answer
The correct answer is: qBd



As d <<< mvqB

d=r sinθ

Impulse is change in momentum




sinθ=dr

where r=mvqB

 d <<< r

sinθ=θ

θ=dr

Change in momentum

=mv θ

=mv × dr=mv×d×qBmv

Impulse=qBd

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