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A charged particle oscillates about its mean equilibrium position with a frequency of $10^9 \mathrm{~Hz}$. The electromagnetic waves produced
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will have frequency of $10^9 \mathrm{~Hz}$
,
will have wavelength of $0.3 \mathrm{~m}$
,
fall in the region of radiowaves
will have frequency of $10^9 \mathrm{~Hz}$
,
will have wavelength of $0.3 \mathrm{~m}$
,
fall in the region of radiowaves
As given that, the frequency of the charged particles oscillates about its mean equilibrium position $=10^9 \mathrm{~Hz}$. Vibrating particle produces electric and magnetic field. So, frequency of electromagnetic waves produced by the charged particle is
$$
v=10^9 \mathrm{~Hz}
$$
$$
\text { Wavelength } \lambda=\frac{\mathrm{c}}{\mathrm{v}}=\frac{3 \times 10^8}{10^9}=0.3 \mathrm{~m}
$$
Since the range of radiowaves is between $10 \mathrm{~Hz}$ to $10^{12} \mathrm{~Hz}$ and hence $10^9 \mathrm{~Hz}$ lies in region of readio waves.
$$
v=10^9 \mathrm{~Hz}
$$
$$
\text { Wavelength } \lambda=\frac{\mathrm{c}}{\mathrm{v}}=\frac{3 \times 10^8}{10^9}=0.3 \mathrm{~m}
$$
Since the range of radiowaves is between $10 \mathrm{~Hz}$ to $10^{12} \mathrm{~Hz}$ and hence $10^9 \mathrm{~Hz}$ lies in region of readio waves.
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