A charged particle q is shot towards another charged particle Q (which is fixed) with a speed v . It approaches Q up to the closest distance r and then returns. If q were given a speed 2 v , the closest distance of approach would be

Question

A charged particle q is shot towards another charged particle Q (which is fixed) with a speed v . It approaches Q up to the closest distance r and then returns. If q were given a speed 2 v , the closest distance of approach would be, r, 2 r, r 2, r 4

MARKS App · Accepted Answer

From conservation of mechanical energy 1 2 m v 2 = k q Q r In second case 1 2 m ( 2 v ⁡ ) 2 = k q Q r ′ r ′ = r 4

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