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Question: Answered & Verified by Expert
A circle which passes through origin and cuts intercepts on axes $a$ and $b$, the equation of circle is
MathematicsCircleJEE Main
Options:
  • A $x^2+y^2-a x-b y=0$
  • B $x^2+y^2+a x+b y=0$
  • C $x^2+y^2-a x+b y=0$
  • D $x^2+y^2+a x-b y=0$
Solution:
2231 Upvotes Verified Answer
The correct answer is: $x^2+y^2-a x-b y=0$
Centre is $\left(\frac{a}{2}, \frac{b}{2}\right)$ and radius $=\sqrt{\frac{a^2+b^2}{4}}$

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