A circuit ABCD is held perpendicular to the uniform magnetic field of B = 5 × 1 0 -2 T extending over the region PQRS and directed into the plane of the paper. The circuit is moving out of the field at a uniform speed of 0 . 2 ms - 1 for 1 . 5 s . During this time, the current in the 5 Ω resistor is

Question

A circuit ABCD is held perpendicular to the uniform magnetic field of B = 5 × 1 0 -2 T extending over the region PQRS and directed into the plane of the paper. The circuit is moving out of the field at a uniform speed of 0 . 2 ms - 1 for 1 . 5 s . During this time, the current in the 5 Ω resistor is, 0.6 mA from B to C, 0.9 mA from B to C, 0.9 mA from C to B, 0.6 mA from C to B

MARKS App · Accepted Answer

I = B ℓ v R I = 5 × 1 0 - 2 × 0.3 × 0.2 5 A = 0.6 mA. Area and flux are decreasing. So, current flows to increase the flux. Clearly, current should be clockwise. So, it flows from B to C through 5 Ω .

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