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A circuit is connected as shown in the figure with the switch $S$ open. When the switch is closed, the total amount of charge that flows from $Y$ to $X$ is

Options:

Solution:
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Verified Answer
The correct answer is:
$27 \mu \mathrm{C}$
$27 \mu \mathrm{C}$
From $Y$ to $X$ charge flows to plates $a$ and $b$.
$$
\left(q_0+q_b\right)_i=0,\left(q_0+q_b\right)_f=27 \mu \mathrm{C}
$$


$\therefore 27 \mu \mathrm{C}$ charge flows from $Y$ to $X$.
$\therefore$ Correct option is (c)
$$
\left(q_0+q_b\right)_i=0,\left(q_0+q_b\right)_f=27 \mu \mathrm{C}
$$


$\therefore 27 \mu \mathrm{C}$ charge flows from $Y$ to $X$.
$\therefore$ Correct option is (c)
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