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A circular $A B C D$ carrying a current ' $i$ ' is placed in a uniform magnetic field, if the magnetic force on the segment $A B$ is $\vec{F}$, the force on the remaining segment BCDA is:
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Verified Answer
The correct answer is:
$-\vec{F}$
We know that net magnetic force on a current loop in a uniform magnetic field is zero.
$$
\begin{aligned}
& \therefore \quad F_{A B}+F_{C B A D}=0 \\
& \therefore \quad \vec{F}_{C B A D}=-\vec{F}_{A B}=-\vec{F} \\
&
\end{aligned}
$$
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