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A circular arc of radius 'r' carrying current 'I' subtends on angle $\frac{\pi}{16}$ at its centre. The radius of a metal wire is uniform. The magnetic induction at the centre of
cirçlar arç is
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cirçlar arç is
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Verified Answer
The correct answer is:
$\frac{\mu_{0} I}{64 r}$
$B_{a t 0}=\frac{\mu_{0} I}{4 \pi \varepsilon}\left(\frac{\pi}{1}\right.)$
$B_{a t 0}=\frac{\mu_{0} I}{64 \varepsilon}$

$B_{a t 0}=\frac{\mu_{0} I}{64 \varepsilon}$

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