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A circular current loop of magnetic moment \( M \) is in an arbitrary orientation in an external
uniform magnetic field \( \vec{B} \). The work done to rotate the loop by \( 30^{\circ} \) about an axis perpendicular
to its plane is
Options:
uniform magnetic field \( \vec{B} \). The work done to rotate the loop by \( 30^{\circ} \) about an axis perpendicular
to its plane is
Solution:
1104 Upvotes
Verified Answer
The correct answer is:
Zero
(C)
Even though the coil is rotated, about an axis perpendicular to its plane, the potential energy does not change. Hence,
work done is zero.
Even though the coil is rotated, about an axis perpendicular to its plane, the potential energy does not change. Hence,
work done is zero.
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