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A circular wheel with 10 spokes with its plane vertical along East-West is rotating about its natural axis with a uniform speed 100 revolutions per minute in the earth's magnetic field. Radius of the wheel is $0.3 \mathrm{~m}$. If the emf induced between the centre of the wheel and the rim is $3 \pi \mu \mathrm{V}$, angle of dip at the place is
(Vertical component of the earth's magnetic field $\mathrm{B}_{\mathrm{V}}=15 \mu \mathrm{T}$ )
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(Vertical component of the earth's magnetic field $\mathrm{B}_{\mathrm{V}}=15 \mu \mathrm{T}$ )
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Verified Answer
The correct answer is:
$\tan ^{-1}\left(\frac{3}{4}\right)$
No solution. Refer to answer key.
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