A closed organ pipe of length L L 4 is in resonance with a tuning fork. If a hole is made in the pipe at a distance L/4 from closed-end, it will be in resonance again, when :

Question

A closed organ pipe of length L L 4 is in resonance with a tuning fork. If a hole is made in the pipe at a distance L/4 from closed-end, it will be in resonance again, when :, Tuning fork is replaced by another of high frequency., Tuning fork is replaced by another of lower frequency., It will be resonance with same tuning fork., Now the pipe will never resonate with any tuning fork.

MARKS App · Accepted Answer

Standing wave cannot be formed. It becomes combination of two pipes one closed and other open pipe. They will not satisfy the condition of standing wave simultaneously. n 1 V 2 ( 3 L 4 ) = n 2 V 4 ( L 4 ) n 1 2 V 3 L = n 2 V L = V 4 L n 1 = 3 8 n 2 = 1 4 Which are not integer so not possible

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