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A closed vessel explodes at $15 \mathrm{~atm}$ pressure. If temperature of the vessel is $300 \mathrm{~K}$ at $10 \mathrm{~atm}$ pressure then find at what temperature will vessel explodes
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The correct answer is:
$450 \mathrm{~K}$
For a closed vessel,
$\begin{aligned} & \frac{P_1}{T_1}=\frac{P_2}{T_2} \Rightarrow \frac{10}{300}=\frac{15}{T_2} \\ & T_2=450 \mathrm{~K}\end{aligned}$
$\begin{aligned} & \frac{P_1}{T_1}=\frac{P_2}{T_2} \Rightarrow \frac{10}{300}=\frac{15}{T_2} \\ & T_2=450 \mathrm{~K}\end{aligned}$
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