A coil has self inductance L = 0 . 04 H and resistance R = 12 Ω . When it is connected to 220 V , 50 Hz supply; what will be the current flowing through the coil?

Question

A coil has self inductance L = 0 . 04 H and resistance R = 12 Ω . When it is connected to 220 V , 50 Hz supply; what will be the current flowing through the coil?, 12 . 7 A, 14 . 7 A, 11 . 7 A, 10 . 7 A

MARKS App · Accepted Answer

L = 0 . 04 H R = 12 Ω V = 220 V , 50 Hz Impedance z = R 2 + w 2 z 2 w = 2 π f = 2 π × 50 = 100 π z = 144 + 100 π 2 × 0.04 2 = 17.38 i = v z = 220 17.38 = 12.7 A .

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