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A coil having $n$ turns and resistance $4 \mathrm{R} \Omega$. This combination is moved in time $t$ seconds from a magnetic field $W_1$ weber to $W_2$ weber. The induced current in the circuit is
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The correct answer is:
$-\frac{\left(\mathrm{W}_2-\mathrm{W}_1\right)}{5 \mathrm{Rt}}$
$-\frac{\left(\mathrm{W}_2-\mathrm{W}_1\right)}{5 \mathrm{Rt}}$
$\mathrm{I}=-\frac{\mathrm{I}}{\mathrm{R}^{\prime}} \frac{\mathrm{d} \phi}{\mathrm{dt}}$
or, I $=-\frac{1}{R^{\prime}} \mathrm{n}\left[\frac{\mathrm{W}_2-\mathrm{W}_1}{\mathrm{t}_2-\mathrm{t}_1}\right]$
( $W_1$ and $W_2$ are not the magnetic field, but the values of flux associated with one turn of coil) $I=\frac{-1}{(R+4 R)} \frac{n\left(W_2-W_1\right)}{t}$
or, $\mathrm{I}=-\frac{\mathrm{n}\left(\mathrm{W}_2-\mathrm{W}_1\right)}{5 \mathrm{Rt}}$
or, I $=-\frac{1}{R^{\prime}} \mathrm{n}\left[\frac{\mathrm{W}_2-\mathrm{W}_1}{\mathrm{t}_2-\mathrm{t}_1}\right]$
( $W_1$ and $W_2$ are not the magnetic field, but the values of flux associated with one turn of coil) $I=\frac{-1}{(R+4 R)} \frac{n\left(W_2-W_1\right)}{t}$
or, $\mathrm{I}=-\frac{\mathrm{n}\left(\mathrm{W}_2-\mathrm{W}_1\right)}{5 \mathrm{Rt}}$
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