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A coil having $N$ turns carry a current / as shown in the figure. The magnetic field intensity at point $P$ is
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Verified Answer
The correct answer is:
$\frac{\mu_0 N / R^2}{2\left(R^2+x^2\right)^{3 / 2}}$
Magnetic field intensity at point $\mathrm{P}$, shown in figure while carrying current "i" and having "N" turns is given by Magnetic field $\mathrm{P}$ due to entire loop is
$\frac{\mu_0 \text { NIR }^2}{2\left(\mathrm{R}^2+\mathrm{x}^2\right)^{3 / 2}}$
$\frac{\mu_0 \text { NIR }^2}{2\left(\mathrm{R}^2+\mathrm{x}^2\right)^{3 / 2}}$
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