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Question: Answered & Verified by Expert
A coil having $N$ turns carry a current as shown in the figure. The magnetic field intensity at point $P$ is

PhysicsMagnetic Effects of CurrentJIPMERJIPMER 2005
Options:
  • A $\frac{\mu_0 N i R^2}{2\left(R^2+x^2\right)^{3 / 2}}$
  • B $\frac{\mu_0 N i}{2 R}$
  • C $\frac{\mu_0 N i R^2}{(R+x)^2}$
  • D zero
Solution:
1558 Upvotes Verified Answer
The correct answer is: $\frac{\mu_0 N i R^2}{2\left(R^2+x^2\right)^{3 / 2}}$
From the formula, magnetic field intensity at point $P$, shown in given figure while coil carry current $i$ and having $N$ turns is given by
$\frac{\mu_0 N i R^2}{2\left(R^2+x^2\right)^{3 / 2}}$

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