Inductive reactance is $X_L=\omega L=2\pi fL=2\pi \times 350\times 0.1=219.9 \mathrm{\Omega }$

Now, total reactance is $X=X_L$

Phase difference is $\tan \varphi =\frac{X}{R}=\frac{{\displaystyle 219.9}}{110}=1.99\approx 2$

Hence, phase difference between the voltage maximum and the current maximum is $\varphi ={\tan }^{-1}\left(2\right)$.