Search any question & find its solution
Question:
Answered & Verified by Expert
A coil of inductance $300 \mathrm{mH}$ and resistance $2 \Omega$ is connected to a source of voltage 2V. The current reaches half of its steady state value in
Options:
Solution:
1463 Upvotes
Verified Answer
The correct answer is:
$0.1 \mathrm{~s}$
$0.1 \mathrm{~s}$
$\mathrm{I}=\mathrm{I}_{\circ}\left(1-\mathrm{e}^{-\frac{\mathrm{R}}{\mathrm{L}}\mathrm{t}}\right)$
$0.693=\frac{\mathrm{R}}{\mathrm{L}} \mathrm{t}$
$\mathrm{t}=\frac{.3 \times 0.693}{2}=0.1 \mathrm{sec}$
$0.693=\frac{\mathrm{R}}{\mathrm{L}} \mathrm{t}$
$\mathrm{t}=\frac{.3 \times 0.693}{2}=0.1 \mathrm{sec}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.