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A coil of resistance $10 \Omega$ and an inductance $5 \mathrm{H}$ is connected to a 100 volt battery. Then energy stored in the coil is
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$250 \mathrm{~J}$
$U=\frac{1}{2} L i^2 \Rightarrow$ $U=\frac{1}{2} \times 5 \times\left(\frac{100}{10}\right)^2=250 \mathrm{~J}$
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