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A coil of resistance $10 \Omega$ and inductance $5 \mathrm{H}$ is connected to a $100 \mathrm{~V}$ battery. Then the energy stored in the coil is
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$250 \mathrm{~J}$
Final current, $\mathrm{I}=\frac{E}{R}=10 \mathrm{~A}$
Energystored in the magnetic field
$\begin{array}{l}
\mathrm{U}=\frac{1}{2} L i \\
\frac{1}{2} \times 5 \times(10)^{2}=250 \mathrm{~J}
\end{array}$
Energystored in the magnetic field
$\begin{array}{l}
\mathrm{U}=\frac{1}{2} L i \\
\frac{1}{2} \times 5 \times(10)^{2}=250 \mathrm{~J}
\end{array}$
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