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Question: Answered & Verified by Expert
A coil of wire of resistance 50 Ω is embedded in a block of ice and a potential difference of 210 V is applied across it. The amount of ice which melts in 1 second is [latent heat of fusion of ice = 80 cal g-1]
PhysicsCurrent ElectricityNEET
Options:
  • A 0.262 g
  • B 2.62 g
  • C 26.2 g
  • D 0.0262 g
Solution:
1789 Upvotes Verified Answer
The correct answer is: 2.62 g
Energy of melting is provided by electric energy therefore
mL=V2Rt
m(80)=(210)250(1)
m=2.62 g

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