Search any question & find its solution
Question:
Answered & Verified by Expert
A coin is tossed and a die is thrown. The probability that the outcome will be head or a number greater than 4 or both, is
Options:
Solution:
1902 Upvotes
Verified Answer
The correct answer is:
$\frac{2}{3}$
The probability of getting head when a coin is thrown $=\frac{1}{2}$ The probability of getting a number greater than 4 when a die is thrown
$$
=\frac{2}{6}=\frac{1}{3}
$$
Hence required probability $=\left(\frac{1}{2}\right)\left(\frac{2}{3}\right)+\left(\frac{1}{2}\right)\left(\frac{1}{3}\right)+\left(\frac{1}{2}\right)\left(\frac{1}{3}\right)=\frac{4}{6}=\frac{2}{3}$
$$
=\frac{2}{6}=\frac{1}{3}
$$
Hence required probability $=\left(\frac{1}{2}\right)\left(\frac{2}{3}\right)+\left(\frac{1}{2}\right)\left(\frac{1}{3}\right)+\left(\frac{1}{2}\right)\left(\frac{1}{3}\right)=\frac{4}{6}=\frac{2}{3}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.