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A coin is tossed twice, what is the probability that at least one tail occurs?
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The sample space of the given experiment is given by $S=\{H H, H T, T H, T T\}$
Let $A$ be the event of getting at least one tail. Then, $A=\{H T, T H, T T\}$
$\therefore P(A)=\frac{n(A)}{n(S)}=\frac{3}{4}$
Let $A$ be the event of getting at least one tail. Then, $A=\{H T, T H, T T\}$
$\therefore P(A)=\frac{n(A)}{n(S)}=\frac{3}{4}$
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