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A colloidal solution is subjected to an electric field than colloidal particles more towards anode. The amount of electrolytes of $\mathrm{BaCl}_{2}, \mathrm{AlCl}_{3}$ and $\mathrm{NaCl}$ required to coagulate the given colloid is in the order
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The correct answer is:
$\mathrm{NaCl}>\mathrm{BaCl}_{2}>\mathrm{AlCl}_{3}$
The amount of electrolyte required to coagulate the given colloid is in order
$\mathrm{NaCl}>\mathrm{BaCl}_{2} < \mathrm{AlCl}_{3}$
Because as colloids move towards anode they must be negatively charge.
According to Hardy Schulze rule,
Coagulation value
$\propto \frac{1}{\text { Coagulating power (Charge an electrolyte) }}$
The charge on the electrolyte; $\mathrm{Na}^{+}, \mathrm{Ba}^{2+}$ and $\mathrm{Al}^{3+}$ are 1,2 and 3 respectively.
$\mathrm{NaCl}>\mathrm{BaCl}_{2} < \mathrm{AlCl}_{3}$
Because as colloids move towards anode they must be negatively charge.
According to Hardy Schulze rule,
Coagulation value
$\propto \frac{1}{\text { Coagulating power (Charge an electrolyte) }}$
The charge on the electrolyte; $\mathrm{Na}^{+}, \mathrm{Ba}^{2+}$ and $\mathrm{Al}^{3+}$ are 1,2 and 3 respectively.
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