Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A combination of parallel plate capacitors is maintained at a certain potential difference.



When a 3 mm thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between the plates is increased by 2.4 mm. Find the dielectric constant of the slab.
PhysicsCapacitanceJEE Main
Options:
  • A 6
  • B 4
  • C 3
  • D 5
Solution:
2844 Upvotes Verified Answer
The correct answer is: 5


Assume initial separation as 3 mm

each capacitance C1=ε0A3 before

C 1 = k ε 0 A 3 . ε 0 A 2.4 k ε 0 A 3 + ε 0 A 2.4

to get same capacitance ε0A3=kε0A3 .ε0A2.4kε0A3+ε0A2.4

3k=2.4k+3

0.6k=3k=30.6

k=306=5.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.