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Question: Answered & Verified by Expert
A comet of mass 108 kg travels around the Sun in an elliptical orbit. When it is closest to the Sun it is 2.5×1011 m away and its speed is 2×104 m s-1 . Find the change in kinetic energy when it is farthest from the Sun and is 5×1010 m away from the Sun
PhysicsGravitationNEET
Options:
  • A 38×108 J
  • B 48×108 J
  • C 58×108 J
  • D 56×108 J
Solution:
2417 Upvotes Verified Answer
The correct answer is: 48×108 J
From the conservation of angular momentum,

v1r1=v2r2

   v2=2×104×2.5×10115×1010=105 m s-1

Change in kinetic energy is,

ΔKE=12×1081052-4×108=48×108 J

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