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A committee of two persons is contituted from two men and two women. What is the probability that the committee will have only women?
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$\frac{1}{6}$
$2 \mathrm{Men}+2$ Women Required probability $=\frac{{ }^{2} \mathrm{C}_{0} \times{ }^{2} \mathrm{C}_{2}}{{ }^{4} \mathrm{C}_{2}}=\frac{1 \times 1}{6}=\frac{1}{6}$
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