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A complex compound in which the oxidation number of a metal is zero is
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Verified Answer
The correct answer is:
$\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]$
CO is a neutral ligand, so the oxidation state of metal in metal carbonyls is always zero.
$$
\begin{array}{r}
{\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]} \\
\mathrm{x}+(0 \times 4)=0 \\
\mathrm{x}=0
\end{array}
$$
$$
\begin{array}{r}
{\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]} \\
\mathrm{x}+(0 \times 4)=0 \\
\mathrm{x}=0
\end{array}
$$
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