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Question: Answered & Verified by Expert
A composite slab consists of two slabs A and B of different materials but of the same thickness placed one on top of the other. The thermal conductivities of A and B are k1 and k2 respectively. A steady temperature difference of 12 °C is maintained across the composite slab. If k1=k22, the temperature difference across the slab A will be
PhysicsThermal Properties of MatterNEET
Options:
  • A 4°C
  • B 8°C
  • C 12°C
  • D 16°C
Solution:
1294 Upvotes Verified Answer
The correct answer is: 8°C


For slab A ,

ΔQΔt=k1Al2ΔT1

For slab B ,

ΔQΔt=k2Al2ΔT2

   k1Al2ΔT1=k2Al2ΔT2

k22ΔT1=k212-ΔT2

ΔT1=24-2ΔT1

ΔT1=8 °C

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