A compound contains 1.08 mol of Na, 0.539 mol of Cu and 2.16 mol of F. Its aqueous solution shows osmotic pressure which is three times that of urea having same molar concentration. The formula of the compound is :

Question

A compound contains 1.08 mol of Na, 0.539 mol of Cu and 2.16 mol of F. Its aqueous solution shows osmotic pressure which is three times that of urea having same molar concentration. The formula of the compound is :, Na 4 [CuF 6 ], Na[CuF 4 ], Na 2 [CuF 4 ], Na 2 [CuF 3 ]

MARKS App · Accepted Answer

Mol ratio of Na, Cu and F = 1 . 0 8 0 . 5 3 9 : 0 . 5 3 9 0 . 5 3 9 : 2 . 1 6 0 . 5 3 9 = 2 : 1 : 4 Empirical formula = Na 2 CuF 4 : Van't Hoff factor (i) = 3 (given) Hence, formula of the compound : Na 2 [CuF 4 ] → 2Na + + [CuF 4 ] 2-

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