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A compound $\left(M_2 \mathrm{O}_2\right)$ of group I element $(M)$ hydrolyses to form $M^{+}, \mathrm{OH}^{-}$and $X$. Another compound $\left(M^{\prime} \mathrm{O}_2\right)$ of group I element $\left(M^{\prime}\right)$ hydrolyses to form $\left(M^{\prime}\right)^{+}, \mathrm{OH}^{-}, X$ and $Y$. What are $X$ and $Y$ respectively ?
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The correct answer is:
$\mathrm{H}_2 \mathrm{O}_2, \mathrm{O}_2$
$M_2 \mathrm{O}_2 \longrightarrow M^{+}+\mathrm{OH}^{-}$and $x=\left(\mathrm{H}_2 \mathrm{O}_2\right.$ peroxide $)$
$$
M^{\prime} \mathrm{O}_2 \longrightarrow M^{+}+\mathrm{OH}^{\prime}, M^{\prime}+\mathrm{O}_2 y=\left(\mathrm{O}_2=\text { Oxygen }\right)
$$
$$
M^{\prime} \mathrm{O}_2 \longrightarrow M^{+}+\mathrm{OH}^{\prime}, M^{\prime}+\mathrm{O}_2 y=\left(\mathrm{O}_2=\text { Oxygen }\right)
$$
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