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A compound of 'A' and 'B' crystallises in a cubic lattice in which 'A' atoms occupy the lattice points at the corners of the cube. The ' $B$ ' atoms occupy the centre of each face of the cube. The probable empirical formula of the compound is
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$\mathrm{AB}_{3}$
$A$ occupies corners, thus number of $A$ atoms per unit cell $=8 \times \frac{1}{8}=1$
$B$ occupies face centres, thus number of $B$ atoms per unit cell $=6 \times \frac{1}{2}=3$
$\therefore$ The empirical formula of the compound is $\mathrm{AB}_{3}$.
$B$ occupies face centres, thus number of $B$ atoms per unit cell $=6 \times \frac{1}{2}=3$
$\therefore$ The empirical formula of the compound is $\mathrm{AB}_{3}$.
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