A compound with molecular formula $ \mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}_{4} $ on acylation with acetic anhydride gives a compound with molecular formula $ \mathrm{C}_{12} \mathrm{H}_{18} \mathrm{O}_{8} $. How many hydroxyl groups are present in the compound?

Question

A compound with molecular formula $ \mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}_{4} $ on acylation with acetic anhydride gives a compound with molecular formula $ \mathrm{C}_{12} \mathrm{H}_{18} \mathrm{O}_{8} $. How many hydroxyl groups are present in the compound?, 1, 2, 3, 4

MARKS App · Accepted Answer

Acylation is used to determine the number of - OH group in the compound. R - OH ⟶ R - OCOCH 3 ​Acylation of one hydroxyl group results in the increment of - COCH 2 (or C 2 H 2 O ). In the question, there is an increment of ( C 8 H 8 O 4 ). Hence, there should be four - OH groups. − OH + ( CH 3 CO ) 2 O → − OCOCH 3 + CH 3 COOH

Search any question & find its solution

Looking for more such questions to practice?