A compound $X$, of boron reacts with $\mathrm{NH}_3$ on heating to give another compound $Y$, which is called inorganic benzene. The compound $X$ can be prepared by treating $\mathrm{BF}_3$ with lithium aluminium hydride. The compounds $X$ and $Y$ are represented by the formulas.

Question

A compound $X$, of boron reacts with $\mathrm{NH}_3$ on heating to give another compound $Y$, which is called inorganic benzene. The compound $X$ can be prepared by treating $\mathrm{BF}_3$ with lithium aluminium hydride. The compounds $X$ and $Y$ are represented by the formulas., $\mathrm{B}_2 \mathrm{H}_6, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6$, $\mathrm{B}_2 \mathrm{O}_3, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6$, $\mathrm{BF}_3, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6$, $\mathrm{B}_3 \mathrm{~N}_3 \mathrm{H}_6, \mathrm{~B}_2 \mathrm{H}_6$

MARKS App · Accepted Answer

$\mathrm{BF}_3 \xrightarrow[-\mathrm{LiF},-\mathrm{AlF}_3]{\mathrm{LiAlH}_4} \underset{(X)}{\mathrm{B}_2 \mathrm{H}_6} \xrightarrow[-\mathrm{H}_2]{\mathrm{NH}_3 / \Delta} \underset{(Y)}{\mathrm{B}_3 \mathrm{~N}_3 \mathrm{H}_6}$ $(X) \Rightarrow \mathrm{B}_2 \mathrm{H}_6$ (Diborane) $(Y) \Rightarrow \mathrm{B}_3 \mathrm{~N}_3 \mathrm{H}_6$ (Borazine or inorganic benzene)

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