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A compound $\mathrm{Z}$ with molecular formula $\mathrm{C}_3 \mathrm{H}_9 \mathrm{~N}$ reacts with $\mathrm{C}_6 \mathrm{H}_5 \mathrm{SO}_2 \mathrm{Cl}$ to give a solid, insoluble in alkali. Idenfity $\mathrm{Z}$.
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Since, $\mathrm{Z}$ on reaction with $\mathrm{C}_6 \mathrm{H}_5 \mathrm{SO}_2 \mathrm{Cl}$ gives a product insoluble in alkali. Therefore, the product does not have a replaceable shows that $\mathrm{Z}$ is a secondary amine.
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