Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A concave lens made of material of refractive index $1.6$ is immersed in a medium of refractive index $2.0$. The two surfaces of the concave lens have the same radius of curvature $0.2 \mathrm{~m}$. The lens will behave as a
PhysicsRay OpticsKVPYKVPY 2014 (SA)
Options:
  • A Divergent lens of focal length $0.4 \mathrm{~m}$
  • B Divergent lens of focal length $0.5 \mathrm{~m}$.
  • C Convergent lens of focal length $0.4 \mathrm{~m}$.
  • D Convergent lens of focal length $0.5 \mathrm{~m}$
Solution:
1157 Upvotes Verified Answer
The correct answer is: Convergent lens of focal length $0.5 \mathrm{~m}$


$\frac{1}{F}=\left(\frac{1.6}{2}-1\right)\left(\frac{1}{-0.2}-\frac{1}{0.2}\right)$
$=\frac{0.4}{2} \times \frac{1}{0.1}$
$F=0.5$ converging lens

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.