A condenser of capacitance 10 μF has been charged to 100 V . It is now connected to another uncharged condenser in parallel. The common potential becomes 40 V . The capacitance of another condenser is

Question

A condenser of capacitance 10 μF has been charged to 100 V . It is now connected to another uncharged condenser in parallel. The common potential becomes 40 V . The capacitance of another condenser is, 15 μF, 5 μF, 10 μF, 16 μF

MARKS App · Accepted Answer

15 μF C 1 = 10 μF C 2 = ? V 1 = 100 V V 2 = 0 V c o m m o n = 40 V V c o m m o n = C 1 V 1 + C 2 V 2 C 1 + C 2 40 = 10 100 + 0 10 + C 2 C 2 = 15 μF

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