Search any question & find its solution
Question:
Answered & Verified by Expert
A conducting circular loop of radius $r$ carries a constant current $i .$ It is placed in a uniform magnetic field $\overrightarrow{\mathrm{B}}_{0}$ such that $\overrightarrow{\mathrm{B}}_{0}$ is perpendicular to the plane of the loop. The magnetic force acting on the loop is
Options:
Solution:
2489 Upvotes
Verified Answer
The correct answer is:
zero
The magnetic field is perpendicular to the plane of the paper. Let us consider two diametrically opposite elements. By Fleming's Left hand rule on element $\mathrm{AB}$ the direction of force will be Leftwards and the magnitude will be
$$
\mathrm{dF}=\operatorname{Idl} \mathrm{B} \sin 90^{\circ}=\mathrm{IdIB}
$$
$$
\mathrm{dF}=\operatorname{Idl} \mathrm{B} \sin 90^{\circ}=\mathrm{IdIB}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.