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Question: Answered & Verified by Expert
A conducting loop (as shown) has total resistance R. A uniform magnetic field B=γt is applied perpendicular to plane of the loop where γ is a constant and t is time. The induced current flowing through loop is

PhysicsElectromagnetic InductionJEE Main
Options:
  • A b2+a2γtR 
  • B b2-a2γR
  • C b2-a2γtR
  • D b2+a2γR
Solution:
2203 Upvotes Verified Answer
The correct answer is: b2-a2γR
Given,

Uniform magnetic field B=γt



Total flux, B1. A1+B2.A2

=Bb2cos0o+Ba2cos180o

=Bb2-Ba2

ϕ=B(b2-a2)

ϕ=γt(b2-a2)

We know that,

Induced current (i) =eR=dϕdtR

From Equation (i),

i=ddt[γtb2-a2]R

i=b2-a2γR

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