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Question: Answered & Verified by Expert
A conducting ring of circular cross-section with inner and outer radii a and b is made out of a material of resistivity ρ. The thickness of the ring is h. It is placed coaxially in a vertical cylindrical region of a magnetic field B=krt, where k is a positive constant, r is the distance from the axis and t is the time. If the current through the ring is I=khαp b3-a3, then what is the value of α?
 
PhysicsElectromagnetic InductionJEE Main
Solution:
1097 Upvotes Verified Answer
The correct answer is: 9


The flux through the area of radius r is

ϕ=0rkrt2πrdr=2πktr33 

E.M.F. induced,

ϵ=dt=2πkr33

Net induced current is

I=ab2πr3khdr3ρ2πr=kh9ρ b3-a3

   α=9

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