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A conducting rod of length $l$ is falling with a constant velocity $v$ perpendicular to a uniform horizontal magnetic field $B$. The potential difference between its two ends will be
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The correct answer is:
$B l v$
If \(e\) is the induced emf, then according to Faraday's law \(e=-\frac{d \phi}{d t}=-\mathrm{Blv}\)
So, the potential difference between two ends of conducting rods will be \(B v l\).
So, the potential difference between two ends of conducting rods will be \(B v l\).
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