Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A conducting sphere of radius $10 \mathrm{~cm}$ is charged with $10 \mu \mathrm{C}$. Another uncharged sphere of radius $20 \mathrm{~cm}$ is allowed to touch it for some time. After that if the spheres are separated, then surface density of charges on the spheres will be in the ratio of
PhysicsElectrostaticsAIIMSAIIMS 2002
Options:
  • A $1: 4$
  • B $1: 2$
  • C $1: 3$
  • D $1: 1$.
Solution:
2017 Upvotes Verified Answer
The correct answer is: $1: 2$
Radius of conducting sphere $\left(R_1\right)=10 \mathrm{~cm}$ charge on the conducting sphere $=10 \mu \mathrm{C}$ and radius of uncharged sphere $\left(R_2\right)=20 \mathrm{~cm}$ For a spherical conductor, the density of charge is proportional to its radius. Therefore ratio of density of charges of the spheres will be $1: 2$.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.