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Question: Answered & Verified by Expert
A conductivity cell has two electrodes $18 \mathrm{~mm}$ apart and having cross sectional area $2.0 \mathrm{~cm}^2$. What is value of cell constant?
ChemistryElectrochemistryMHT CETMHT CET 2022 (07 Aug Shift 2)
Options:
  • A $0.9 \mathrm{~cm}^{-1}$
  • B $0.18 \mathrm{~cm}^{-1}$
  • C $3.6 \mathrm{~cm}^{-1}$
  • D $0.2 \mathrm{~cm}^{-1}$
Solution:
2704 Upvotes Verified Answer
The correct answer is: $0.9 \mathrm{~cm}^{-1}$
Cell constant $=\frac{\mathrm{L}}{\mathrm{A}}=\frac{1.8}{2}=0.9 \mathrm{~cm}^{-1}$

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