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A conductor of $3 \mathrm{~m}$ in length is moving perpendicularly to magnetic field of $10^{-3}$ tesla with the speed of $10^2 \mathrm{~m} / \mathrm{s}$, then the e.m.f. produced across the ends of conductor will be
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$0.3$ volt
$e=B v l=3 \times 10^{-3} \times 10^2=0.3 \mathrm{~volt}$
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