A conductor wire carrying current i is placed parallel to a long conducting sheet having a current per unit width j 0 and width d , as shown in the figure. the force per unit length on the conductor wire will be

Question

A conductor wire carrying current i is placed parallel to a long conducting sheet having a current per unit width j 0 and width d , as shown in the figure. the force per unit length on the conductor wire will be, μ 0 j 0 i π tan - 1 d 2 h - k ^, μ 0 j 0 i π tan - 1 2 h d - k ^, j 0 i μ 0 π tan - 1 2 h d - k ^, j 0 i μ 0 π tan - 1 d 2 h - k ^

MARKS App · Accepted Answer

​ F = 2 ∫ dF sin θ = 2 ∫ μ 0 4 π 2 j 0 dx . i h 2 + x 2 . sin θ = μ 0 π j 0 i ∫ ​ d x h 2 + x 2 · h h 2 + x 2 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLnhiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yqaqpepae9pg0FirpepeKkFr0xfr=xfr=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@51FD@ = μ 0 π j 0 i · h ∫ 0 d / 2 dx h 2 + x 2 = μ 0 π j 0 i h 1 h tan -1 x h 0 d / 2 F → = μ 0 j 0 i π tan -1 d 2h - k ^

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