A conductor with a cavity is charged positively and its surface charge density is σ . If E and V represent the electric field and potential, then inside the cavity

Question

A conductor with a cavity is charged positively and its surface charge density is σ . If E and V represent the electric field and potential, then inside the cavity, E = 0 and V = 0, E = 0 and σ = constant, V = 0 and σ = constant, E = 0 and V = constant

MARKS App · Accepted Answer

Surface charge density = σ Inside the surface, the electric field is zero. ⇒ E i n s i d e = 0 ∵ V i n s i d e = V s u r f a c e The potential inside the surface of charged sphere is constant ∴ E = 0 , V = constant.

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