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A constant force acting on a body of mass $3.0 \mathrm{~kg}$ changes its speed from $2.0 \mathrm{~m} / \mathrm{s}^{-1}$ to $3.5 \mathrm{~m} / \mathrm{s}^{-1}$ in $25 \mathrm{~s}$. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?
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Here, $m=3.0 \mathrm{~kg}, u=2.0 \mathrm{~ms}^{-1}$ and $v=3.5 \mathrm{~ms}^{-1}$, $t=25 \mathrm{~s}$
Now, $F=m a=m(v-u) / t$
$$
=3.0(3.5-2.0) / 25=0.18 \mathrm{~N}
$$
$\therefore$ the force is along the direction of motion.
Now, $F=m a=m(v-u) / t$
$$
=3.0(3.5-2.0) / 25=0.18 \mathrm{~N}
$$
$\therefore$ the force is along the direction of motion.
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